Odds of exact hand 2x in a row?

[GainerRakeback]

So I'm on UB tonight, and I get the exact same hand (including suits) twice in a row. Will someone good at math tell me the odds of that happening?

Hand #55255902-62082 at Pegram (No Limit Hold'em)
Started at 01/Oct/08 20:07:45


XEXPO: -- --
jayjay54: -- --
KPM59: -- --
standish: -- --
Donkovich: -- --
FullGainer271: 8c Qs
Shikoro: -- --
DamselGZ: -- --
Dsmith21: -- --

----------------------------------------------------------------
----------------------------------------------------------------

Started at 01/Oct/08 20:07:45

XEXPO: -- --
jayjay54: -- --
KPM59: -- --
standish: -- --
Donkovich: -- --
FullGainer271: 8c Qs
Shikoro: -- --
DamselGZ: -- --
Dsmith21: -- --

Pre-flop:

Dsmith21 folds. XEXPO folds. jayjay54 calls.
KPM59 folds. standish calls. Donkovich raises to
$2.75. FullGainer271 folds. Shikoro folds.
DamselGZ folds. jayjay54 folds. standish calls.



I think online poker and hand distribution is legit, but this is strange still.

[gamer4life27]

Odds of getting any particular two card combination from a deck of 52 is as such:

52:1 * 51:1 = 2,652:1

Odds of getting any particular two card combination from a deck of 52 back to back (or how many hands to see the same exact hand again) is as such:

2,652:1 * 2,652:1 = 7,033,104:1

I am not sure, but this is what my grade school teacher thought me for card math. It could be either 2,652:1 * 2,652:1, or 2,652:1 + 2,652:1 for 5304:1, but I'm going to lean more to the 7m side of the odds. Lol.

*Again, I am thinking this is totally wrong. Someone please correct me if I'm wrong.

[Wyte22]

You have a better chance of Anna K. giving you mouth to mouth than ever seeing that happen again.

[phaul]

It is 1/26 x 1/51 = 1/1326 because it doesn't matter which card you get first. So actually pretty common. It is the same whether you mean "I just got Q8, what are the odds I'll get that hand again" or "what are the odds I'll get the same hand twice in the next two hands".

Gamer4life, 25:1 is 1/26. 25:1 notation is not useful for working out, it's just for gamblers at bookies.

[allthatremains]

Originally Posted by phaul It is 1/26 x 1/51 = 1/1326 because it doesn't matter which card you get first. So actually pretty common. It is the same whether you mean "I just got Q8, what are the odds I'll get that hand again" or "what are the odds I'll get the same hand twice in the next two hands". Gamer4life, 25:1 is 1/26. 25:1 notation is not useful for working out, it's just for gamblers at bookies.

Correct. - Unless you predicted the exact 2 hands BEFORE the first hand was dealt. In which case the odds would be 1326 x 1326 = 1,758,276.

I'm quite sure you did not "predict" this event happening before the first hand was dealt so it's 1/1326.

Not sure how to calculate the ANNA K. bit, so I'll give you that one.

[frob23]

Yeah, this is actually pretty common. The reason most people don't comment about it is just because the vast majority of Hold'em hands are unplayable and therefore not paid much attention.

If I fold T-5o and get T-5o the very next hand, I am not likely to notice if the suits are exactly the same as the previous hand because the hand before was unremarkable and I don't sit around trying to remember the exact hands I fold.