odds question

[pokerbucket]

Does anyone know the odds of making a full house in Omaha by the river if you flop trips?

[C8H10N4O2]

Does anyone know the odds of making a full house in Omaha by the river if you flop trips?

It probably has a lot to do with what other cards you are holding... I mean if you flop trips but have a pair in your hand as well, the odds will be different etc... Just run the calculation of the number of outs you'd have like you would in hold'em. You just have a lot more outs to count. I'd run the numbers, but I am getting ready to leave. If no one else has done it by later tonight, I'll sit down and do it.

[grimReaper]

http://www.holdemshirts.net/oddscalculator.htm

[pokerbucket]

It probably has a lot to do with what other cards you are holding... I mean if you flop trips but have a pair in your hand as well, the odds will be different etc... Just run the calculation of the number of outs you'd have like you would in hold'em. You just have a lot more outs to count. I'd run the numbers, but I am getting ready to leave. If no one else has done it by later tonight, I'll sit down and do it.

Thanks dew, I want to know the odds if u have trips with 3 other cards available to pair. so you have QK67 and the flop is QQ2

I was also wondering if the odds would be really different if you hit a set so lets say you hold QQj4 and the flop is Q26.

If you can figure out the odds of making a full house for me I would appreciate it...it will help with my heads up strategy when I know I am up against a flush or a straight.

[travz21]

Getting a boat after flopping trips is easier than boating/quading up a flopped set. You have 10 outs twice for ~40%, ~20% per street for boating/quading up trips on the flop. The odds for boating/quading up a flopped set are a little harder. You'll have 7 outs drawing to the turn, which is ~14%. If you miss you'll have 10 outs if the turn isn't one of your other hole cards for ~20% to improve on the river. So at best you'd have ~34% to improve after flopping a set.

I think that's right. I didn't read everything too closely. Just take your outs and multiply by 2 for each street you have left to get your total odds of improving. Pretty simple...even I can kind of do it.

[C8H10N4O2]

Thanks dew, I want to know the odds if u have trips with 3 other cards available to pair. so you have QK67 and the flop is QQ2

I was also wondering if the odds would be really different if you hit a set so lets say you hold QQj4 and the flop is Q26.

If you can figure out the odds of making a full house for me I would appreciate it...it will help with my heads up strategy when I know I am up against a flush or a straight.

In the example you gave you are going to have 10 outs with two draws (this assumes that hitting quads is an out too... if you aren't wanting to figure in quads as well, simply replace 10 with 9 and re-run the calculation below). Travz explained the shortcut way, but if you happen to want to know how to figure out the exact percentage here it is.

It's easiest to calculate based on your chances of "not hitting". To figure this out, since you have 45 cards left in the deck, you want to take (45-10)/45. This gives you the odds of not hitting on the first draw. Then you need to figure out the odds of not hitting on the second draw. Since one card is no longer in the deck, you'll be using 44 now. So you take (44-10)/44. Now that you have your two odds, you have to multiply them together which will give you the odds of both events events happening (which in this case, will give the the odds of not hitting your outs on both draws). Once you get this number (the odds of not hitting your full house/quads), simply subtract it from 1 and you'll have the decimal that you can convert into your % of hitting your full house/quads.

So in short



You can also use this for any number of outs... simply replace 10 with however many outs you believe you have.

[travz21]

Nice artwork.

[C8H10N4O2]

Haha... thanks. It might look horrendous, but I think it gets the point across better than

(1-((45-10)/45)*((44-10)/44))*100=39.89898989%

[pokerbucket]

Haha... thanks. It might look horrendous, but I think it gets the point across better than

(1-((45-10)/45)*((44-10)/44))*100=39.89898989%

Dude 39% im folding but 39.89898989% and im all in

THX